Integrand size = 19, antiderivative size = 185 \[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=-\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}-\frac {d \sqrt [4]{c+d x}}{15 b (b c-a d) (a+b x)^{3/2}}+\frac {d^2 \sqrt [4]{c+d x}}{6 b (b c-a d)^2 \sqrt {a+b x}}+\frac {d^2 \sqrt {-\frac {d (a+b x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{6 b^{5/4} (b c-a d)^{7/4} \sqrt {a+b x}} \]
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Time = 0.11 (sec) , antiderivative size = 185, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {49, 53, 65, 230, 227} \[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=\frac {d^2 \sqrt {-\frac {d (a+b x)}{b c-a d}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right ),-1\right )}{6 b^{5/4} \sqrt {a+b x} (b c-a d)^{7/4}}+\frac {d^2 \sqrt [4]{c+d x}}{6 b \sqrt {a+b x} (b c-a d)^2}-\frac {d \sqrt [4]{c+d x}}{15 b (a+b x)^{3/2} (b c-a d)}-\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}} \]
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Rule 49
Rule 53
Rule 65
Rule 227
Rule 230
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}+\frac {d \int \frac {1}{(a+b x)^{5/2} (c+d x)^{3/4}} \, dx}{10 b} \\ & = -\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}-\frac {d \sqrt [4]{c+d x}}{15 b (b c-a d) (a+b x)^{3/2}}-\frac {d^2 \int \frac {1}{(a+b x)^{3/2} (c+d x)^{3/4}} \, dx}{12 b (b c-a d)} \\ & = -\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}-\frac {d \sqrt [4]{c+d x}}{15 b (b c-a d) (a+b x)^{3/2}}+\frac {d^2 \sqrt [4]{c+d x}}{6 b (b c-a d)^2 \sqrt {a+b x}}+\frac {d^3 \int \frac {1}{\sqrt {a+b x} (c+d x)^{3/4}} \, dx}{24 b (b c-a d)^2} \\ & = -\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}-\frac {d \sqrt [4]{c+d x}}{15 b (b c-a d) (a+b x)^{3/2}}+\frac {d^2 \sqrt [4]{c+d x}}{6 b (b c-a d)^2 \sqrt {a+b x}}+\frac {d^2 \text {Subst}\left (\int \frac {1}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{6 b (b c-a d)^2} \\ & = -\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}-\frac {d \sqrt [4]{c+d x}}{15 b (b c-a d) (a+b x)^{3/2}}+\frac {d^2 \sqrt [4]{c+d x}}{6 b (b c-a d)^2 \sqrt {a+b x}}+\frac {\left (d^2 \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+\frac {b x^4}{\left (a-\frac {b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{6 b (b c-a d)^2 \sqrt {a+b x}} \\ & = -\frac {2 \sqrt [4]{c+d x}}{5 b (a+b x)^{5/2}}-\frac {d \sqrt [4]{c+d x}}{15 b (b c-a d) (a+b x)^{3/2}}+\frac {d^2 \sqrt [4]{c+d x}}{6 b (b c-a d)^2 \sqrt {a+b x}}+\frac {d^2 \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{6 b^{5/4} (b c-a d)^{7/4} \sqrt {a+b x}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.02 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.39 \[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=-\frac {2 \sqrt [4]{c+d x} \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},-\frac {1}{4},-\frac {3}{2},\frac {d (a+b x)}{-b c+a d}\right )}{5 b (a+b x)^{5/2} \sqrt [4]{\frac {b (c+d x)}{b c-a d}}} \]
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\[\int \frac {\left (d x +c \right )^{\frac {1}{4}}}{\left (b x +a \right )^{\frac {7}{2}}}d x\]
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\[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=\int { \frac {{\left (d x + c\right )}^{\frac {1}{4}}}{{\left (b x + a\right )}^{\frac {7}{2}}} \,d x } \]
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\[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=\int \frac {\sqrt [4]{c + d x}}{\left (a + b x\right )^{\frac {7}{2}}}\, dx \]
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\[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=\int { \frac {{\left (d x + c\right )}^{\frac {1}{4}}}{{\left (b x + a\right )}^{\frac {7}{2}}} \,d x } \]
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Exception generated. \[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {\sqrt [4]{c+d x}}{(a+b x)^{7/2}} \, dx=\int \frac {{\left (c+d\,x\right )}^{1/4}}{{\left (a+b\,x\right )}^{7/2}} \,d x \]
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